2x^2-3x+4+3x-x^2-6=

Solution for 2x^2-3x+4+3x-x^2-6= equation:

Simplifying
2x2 + -3x + 4 + 3x + -1x2 + -6 = 0

Reorder the terms:
4 + -6 + -3x + 3x + 2x2 + -1x2 = 0

Combine like terms: 4 + -6 = -2
-2 + -3x + 3x + 2x2 + -1x2 = 0

Combine like terms: -3x + 3x = 0
-2 + 0 + 2x2 + -1x2 = 0
-2 + 2x2 + -1x2 = 0

Combine like terms: 2x2 + -1x2 = 1x2
-2 + 1x2 = 0

Solving
-2 + 1x2 = 0

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '2' to each side of the equation.
-2 + 2 + 1x2 = 0 + 2

Combine like terms: -2 + 2 = 0
0 + 1x2 = 0 + 2
1x2 = 0 + 2

Combine like terms: 0 + 2 = 2
1x2 = 2

Divide each side by '1'.
x2 = 2

Simplifying
x2 = 2

Take the square root of each side:
x = {-1.414213562, 1.414213562}